- 牛顿运动定律英文
牛顿运动定律的英文表述如下：
牛顿第一定律（First Law of Newton）：惯性定律（Law of Inertia）。
牛顿第二定律（Second Law of Newton）：加速度定律（Law of Acceleration）。
牛顿第三定律（Third Law of Newton）：作用与反作用定律（Law of Action and Reaction）。
以上表述为一般性的英文表达，具体使用时可能需要根据语境进行适当调整。
相关例题：
Example Question:
A 2.0-kg mass is attached to the end of a 10-m-long string that is whipped at a constant speed of 2.5 m/s. If the system is suddenly released from rest, how far does the mass move in the first 0.5 s?
Solution:
1. Newton's First Law of Motion: An object at rest tends to remain at rest, and an object in motion tends to remain in motion in a straight line at a constant speed unless acted upon by an unbalanced force.
2. Newton's Second Law of Motion: The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
To solve this problem, we can use the following steps:
1. Determine the tension in the string.
2. Apply Newton's Second Law to find the acceleration of the mass.
3. Use the initial velocity (zero) and acceleration to calculate the distance traveled in the first 0.5 s.
Assuming that the motion is in a straight line, the tension in the string can be calculated using the relationship: T = F = ma, where T is the tension, F is the force, m is the mass, and a is the acceleration.
Since the motion is sudden and there is no time for the mass to accelerate, its velocity remains constant for a short period of time (0.5 s). Therefore, we can use the relationship v = s/t to calculate the distance traveled in this period of time.
Here's the solution:
1. The tension in the string is equal to the product of the mass, acceleration, and velocity: 2 kg x a x 2.5 m/s = 5 N.
2. Using Newton's Second Law, we can calculate the acceleration of the mass: a = F/m = 5 N/2 kg = 2.5 m/s^2.
3. The mass moves a distance of s = vt = 2.5 m/s x 0.5 s = 1.25 m in the first 0.5 s.
Therefore, the mass moves a total distance of 1.75 m (including the initial distance of 10 m).
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