- 牛顿运动定律英语
牛顿运动定律的英语表达如下：
1. 第一定律（Newton's First Law）也称为惯性定律（Law of Inertia）。
2. 第二定律（Newton's Second Law）也称为加速度定律（Law of Acceleration）。
3. 第三定律（Newton's Third Law）也称为作用与反作用定律（Law of Action and Reaction）。
希望以上信息对您有帮助。如果还有其他问题，欢迎随时提问。
相关例题：
例题：
A 2.0 kg box is sliding on a frictionless table towards a 4.0 kg book that is stationary. If the box's velocity is 2.0 m/s, how much force is required to stop it in 2.0 seconds?
解答：
To solve this problem, we need to use Newton's Second Law, F = ma, where F is the force acting on the box, m is its mass, and a is its acceleration.
First, we need to determine the force required to stop the box. Let's call this force Fstop.
Fstop = m astop = 2 kg (v/t) = 2 kg (2 m/s / 2 s) = 2 N
Now, we need to find out the force of friction between the box and the table. Let's call this force Ffriction.
Ffriction = μ mg, where μ is the coefficient of friction and mg is the box's weight (which is 2 kg 9.8 m/s^2).
μ 2 kg 9.8 m/s^2 = Ffriction = Fstop + Fbook
μ 2 kg 9.8 m/s^2 = 2 N + 4 kg g = 4 N
μ = (Fstop + Fbook) / (2 kg g) = (2 N + 4 kg 9.8 m/s^2) / (2 kg 9.8 m/s^2) = 0.75
So, the coefficient of friction is approximately 0.75. This means that the box will experience a frictional force of approximately 1.5 N when it slides towards the book.
Now that we know both forces acting on the box (Fstop and Ffriction), we can calculate its acceleration: a = (Fstop - Ffriction) / m = (2 N - 1.5 N) / 2 kg = 0.25 m/s^2
Finally, we can use this acceleration to determine how much time it takes for the box to stop: t = v / a = 2 m/s / 0.25 m/s^2 = 8 s > 2 s, so it will stop in 8 seconds.
这个问题主要考察了牛顿第二定律的应用，需要理解加速度、质量和力的关系，以及如何根据这些关系来解决问题。
以上是小编为您整理的牛顿运动定律英语，更多2024牛顿运动定律英语及物理学习资料源请关注物理资源网http://www.wuliok.com